# Program to find GCD of floating point numbers

The greatest common divisor (GCD) of two or more numbers, which are not all zero, is the largest positive number that divides each of the numbers.
Example:

```Input  : 0.3, 0.9
Output : 0.3

Input  : 0.48, 0.108
Output : 0.012```

The simplest approach to solve this problem is :

We can do this using the Euclidean algorithm. This algorithm indicates that if the smaller number is subtracted from a bigger number, GCD of two numbers doesn’t change.

`// CPP code for finding the GCD of two floating`
`// numbers.`
`#include <bits/stdc++.h>`
`using` `namespace` `std;`
`// Recursive function to return gcd of a and b`
`double` `gcd(``double` `a, ``double` `b)`
`{`
`    ``if` `(a < b)`
`        ``return` `gcd(b, a);`
`    ``// base case`
`    ``if` `(``fabs``(b) < 0.001)`
`        ``return` `a;`
`    ``else`
`        ``return` `(gcd(b, a - ``floor``(a / b) * b));`
`}`
`// Driver Function.`
`int` `main()`
`{`
`    ``double` `a = 1.20, b = 22.5;`
`    ``cout << gcd(a, b);`
`    ``return` `0;`
`}`

Output:

```0.3

```

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source and credits.
source and credits: http://www.geeksforgeeks.org
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rakesh